| /* Copyright (C) 1991, 1993, 1995, 1997-1998, 2003, 2006, 2009-2026 Free | |
| Software Foundation, Inc. | |
| Contributed by Torbjorn Granlund (tege@sics.se). | |
| NOTE: The canonical source of this file is maintained with the GNU C Library. | |
| Bugs can be reported to bug-glibc@prep.ai.mit.edu. | |
| This file is free software: you can redistribute it and/or modify | |
| it under the terms of the GNU Lesser General Public License as | |
| published by the Free Software Foundation; either version 2.1 of the | |
| License, or (at your option) any later version. | |
| This file is distributed in the hope that it will be useful, | |
| but WITHOUT ANY WARRANTY; without even the implied warranty of | |
| MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the | |
| GNU Lesser General Public License for more details. | |
| You should have received a copy of the GNU Lesser General Public License | |
| along with this program. If not, see <https://www.gnu.org/licenses/>. */ | |
| #ifndef _LIBC | |
| # include <config.h> | |
| #endif | |
| #include <string.h> | |
| #include <stdint.h> | |
| #ifdef _LIBC | |
| # undef memcmp | |
| # include <memcopy.h> | |
| # include <endian.h> | |
| # if __BYTE_ORDER == __BIG_ENDIAN | |
| # define WORDS_BIGENDIAN | |
| # endif | |
| #else /* Not in the GNU C library. */ | |
| # include <sys/types.h> | |
| /* Type to use for aligned memory operations. | |
| This should normally be the biggest type supported by a single load | |
| and store. Must be an unsigned type. */ | |
| # define op_t unsigned long int | |
| # define OPSIZ (sizeof(op_t)) | |
| /* Threshold value for when to enter the unrolled loops. */ | |
| # define OP_T_THRES 16 | |
| /* Type to use for unaligned operations. */ | |
| typedef unsigned char byte; | |
| # ifndef WORDS_BIGENDIAN | |
| # define MERGE(w0, sh_1, w1, sh_2) (((w0) >> (sh_1)) | ((w1) << (sh_2))) | |
| # else | |
| # define MERGE(w0, sh_1, w1, sh_2) (((w0) << (sh_1)) | ((w1) >> (sh_2))) | |
| # endif | |
| #endif /* In the GNU C library. */ | |
| #ifdef WORDS_BIGENDIAN | |
| # define CMP_LT_OR_GT(a, b) ((a) > (b) ? 1 : -1) | |
| #else | |
| # define CMP_LT_OR_GT(a, b) memcmp_bytes (a, b) | |
| #endif | |
| /* BE VERY CAREFUL IF YOU CHANGE THIS CODE! */ | |
| /* The strategy of this memcmp is: | |
| 1. Compare bytes until one of the block pointers is aligned. | |
| 2. Compare using memcmp_common_alignment or | |
| memcmp_not_common_alignment, regarding the alignment of the other | |
| block after the initial byte operations. The maximum number of | |
| full words (of type op_t) are compared in this way. | |
| 3. Compare the few remaining bytes. */ | |
| #ifndef WORDS_BIGENDIAN | |
| /* memcmp_bytes -- Compare A and B bytewise in the byte order of the machine. | |
| A and B are known to be different. | |
| This is needed only on little-endian machines. */ | |
| # ifdef __GNUC__ | |
| __inline | |
| # endif | |
| static int | |
| memcmp_bytes (op_t a, op_t b) | |
| { | |
| const byte *srcp1 = (const byte *) &a; | |
| const byte *srcp2 = (const byte *) &b; | |
| op_t a0, b0; | |
| do | |
| { | |
| a0 = srcp1[0]; | |
| b0 = srcp2[0]; | |
| srcp1 += 1; | |
| srcp2 += 1; | |
| } | |
| while (a0 == b0); | |
| return a0 - b0; | |
| } | |
| #endif | |
| /* memcmp_common_alignment -- Compare blocks at SRCP1 and SRCP2 with LEN 'op_t' | |
| objects (not LEN bytes!). Both SRCP1 and SRCP2 should be aligned for | |
| memory operations on 'op_t's. */ | |
| #ifdef __GNUC__ | |
| __inline | |
| #endif | |
| static int | |
| memcmp_common_alignment (uintptr_t srcp1, uintptr_t srcp2, size_t len) | |
| { | |
| op_t a0, a1; | |
| op_t b0, b1; | |
| switch (len % 4) | |
| { | |
| default: /* Avoid warning about uninitialized local variables. */ | |
| case 2: | |
| a0 = ((op_t *) srcp1)[0]; | |
| b0 = ((op_t *) srcp2)[0]; | |
| srcp1 -= 2 * OPSIZ; | |
| srcp2 -= 2 * OPSIZ; | |
| len += 2; | |
| goto do1; | |
| case 3: | |
| a1 = ((op_t *) srcp1)[0]; | |
| b1 = ((op_t *) srcp2)[0]; | |
| srcp1 -= OPSIZ; | |
| srcp2 -= OPSIZ; | |
| len += 1; | |
| goto do2; | |
| case 0: | |
| if (OP_T_THRES <= 3 * OPSIZ && len == 0) | |
| return 0; | |
| a0 = ((op_t *) srcp1)[0]; | |
| b0 = ((op_t *) srcp2)[0]; | |
| goto do3; | |
| case 1: | |
| a1 = ((op_t *) srcp1)[0]; | |
| b1 = ((op_t *) srcp2)[0]; | |
| srcp1 += OPSIZ; | |
| srcp2 += OPSIZ; | |
| len -= 1; | |
| if (OP_T_THRES <= 3 * OPSIZ && len == 0) | |
| goto do0; | |
| /* Fall through. */ | |
| } | |
| do | |
| { | |
| a0 = ((op_t *) srcp1)[0]; | |
| b0 = ((op_t *) srcp2)[0]; | |
| if (a1 != b1) | |
| return CMP_LT_OR_GT (a1, b1); | |
| do3: | |
| a1 = ((op_t *) srcp1)[1]; | |
| b1 = ((op_t *) srcp2)[1]; | |
| if (a0 != b0) | |
| return CMP_LT_OR_GT (a0, b0); | |
| do2: | |
| a0 = ((op_t *) srcp1)[2]; | |
| b0 = ((op_t *) srcp2)[2]; | |
| if (a1 != b1) | |
| return CMP_LT_OR_GT (a1, b1); | |
| do1: | |
| a1 = ((op_t *) srcp1)[3]; | |
| b1 = ((op_t *) srcp2)[3]; | |
| if (a0 != b0) | |
| return CMP_LT_OR_GT (a0, b0); | |
| srcp1 += 4 * OPSIZ; | |
| srcp2 += 4 * OPSIZ; | |
| len -= 4; | |
| } | |
| while (len != 0); | |
| /* This is the right position for do0. Please don't move | |
| it into the loop. */ | |
| do0: | |
| if (a1 != b1) | |
| return CMP_LT_OR_GT (a1, b1); | |
| return 0; | |
| } | |
| /* memcmp_not_common_alignment -- Compare blocks at SRCP1 and SRCP2 with LEN | |
| 'op_t' objects (not LEN bytes!). SRCP2 should be aligned for memory | |
| operations on 'op_t', but SRCP1 *should be unaligned*. */ | |
| #ifdef __GNUC__ | |
| __inline | |
| #endif | |
| static int | |
| memcmp_not_common_alignment (uintptr_t srcp1, uintptr_t srcp2, size_t len) | |
| { | |
| op_t a0, a1, a2, a3; | |
| op_t b0, b1, b2, b3; | |
| op_t x; | |
| int shl, shr; | |
| /* Calculate how to shift a word read at the memory operation | |
| aligned srcp1 to make it aligned for comparison. */ | |
| shl = 8 * (srcp1 % OPSIZ); | |
| shr = 8 * OPSIZ - shl; | |
| /* Make SRCP1 aligned by rounding it down to the beginning of the 'op_t' | |
| it points in the middle of. */ | |
| srcp1 &= -OPSIZ; | |
| switch (len % 4) | |
| { | |
| default: /* Avoid warning about uninitialized local variables. */ | |
| case 2: | |
| a1 = ((op_t *) srcp1)[0]; | |
| a2 = ((op_t *) srcp1)[1]; | |
| b2 = ((op_t *) srcp2)[0]; | |
| srcp1 -= 1 * OPSIZ; | |
| srcp2 -= 2 * OPSIZ; | |
| len += 2; | |
| goto do1; | |
| case 3: | |
| a0 = ((op_t *) srcp1)[0]; | |
| a1 = ((op_t *) srcp1)[1]; | |
| b1 = ((op_t *) srcp2)[0]; | |
| srcp2 -= 1 * OPSIZ; | |
| len += 1; | |
| goto do2; | |
| case 0: | |
| if (OP_T_THRES <= 3 * OPSIZ && len == 0) | |
| return 0; | |
| a3 = ((op_t *) srcp1)[0]; | |
| a0 = ((op_t *) srcp1)[1]; | |
| b0 = ((op_t *) srcp2)[0]; | |
| srcp1 += 1 * OPSIZ; | |
| goto do3; | |
| case 1: | |
| a2 = ((op_t *) srcp1)[0]; | |
| a3 = ((op_t *) srcp1)[1]; | |
| b3 = ((op_t *) srcp2)[0]; | |
| srcp1 += 2 * OPSIZ; | |
| srcp2 += 1 * OPSIZ; | |
| len -= 1; | |
| if (OP_T_THRES <= 3 * OPSIZ && len == 0) | |
| goto do0; | |
| /* Fall through. */ | |
| } | |
| do | |
| { | |
| a0 = ((op_t *) srcp1)[0]; | |
| b0 = ((op_t *) srcp2)[0]; | |
| x = MERGE (a2, shl, a3, shr); | |
| if (x != b3) | |
| return CMP_LT_OR_GT (x, b3); | |
| do3: | |
| a1 = ((op_t *) srcp1)[1]; | |
| b1 = ((op_t *) srcp2)[1]; | |
| x = MERGE (a3, shl, a0, shr); | |
| if (x != b0) | |
| return CMP_LT_OR_GT (x, b0); | |
| do2: | |
| a2 = ((op_t *) srcp1)[2]; | |
| b2 = ((op_t *) srcp2)[2]; | |
| x = MERGE (a0, shl, a1, shr); | |
| if (x != b1) | |
| return CMP_LT_OR_GT (x, b1); | |
| do1: | |
| a3 = ((op_t *) srcp1)[3]; | |
| b3 = ((op_t *) srcp2)[3]; | |
| x = MERGE (a1, shl, a2, shr); | |
| if (x != b2) | |
| return CMP_LT_OR_GT (x, b2); | |
| srcp1 += 4 * OPSIZ; | |
| srcp2 += 4 * OPSIZ; | |
| len -= 4; | |
| } | |
| while (len != 0); | |
| /* This is the right position for do0. Please don't move | |
| it into the loop. */ | |
| do0: | |
| x = MERGE (a2, shl, a3, shr); | |
| if (x != b3) | |
| return CMP_LT_OR_GT (x, b3); | |
| return 0; | |
| } | |
| int | |
| rpl_memcmp (const void *s1, const void *s2, size_t len) | |
| { | |
| op_t a0; | |
| op_t b0; | |
| uintptr_t srcp1 = (uintptr_t) s1; | |
| uintptr_t srcp2 = (uintptr_t) s2; | |
| op_t res; | |
| if (len >= OP_T_THRES) | |
| { | |
| /* There are at least some bytes to compare. No need to test | |
| for LEN == 0 in this alignment loop. */ | |
| while (srcp2 % OPSIZ != 0) | |
| { | |
| a0 = ((byte *) srcp1)[0]; | |
| b0 = ((byte *) srcp2)[0]; | |
| srcp1 += 1; | |
| srcp2 += 1; | |
| res = a0 - b0; | |
| if (res != 0) | |
| return res; | |
| len -= 1; | |
| } | |
| /* SRCP2 is now aligned for memory operations on 'op_t'. | |
| SRCP1 alignment determines if we can do a simple, | |
| aligned compare or need to shuffle bits. */ | |
| if (srcp1 % OPSIZ == 0) | |
| res = memcmp_common_alignment (srcp1, srcp2, len / OPSIZ); | |
| else | |
| res = memcmp_not_common_alignment (srcp1, srcp2, len / OPSIZ); | |
| if (res != 0) | |
| return res; | |
| /* Number of bytes remaining in the interval [0..OPSIZ-1]. */ | |
| srcp1 += len & -OPSIZ; | |
| srcp2 += len & -OPSIZ; | |
| len %= OPSIZ; | |
| } | |
| /* There are just a few bytes to compare. Use byte memory operations. */ | |
| while (len != 0) | |
| { | |
| a0 = ((byte *) srcp1)[0]; | |
| b0 = ((byte *) srcp2)[0]; | |
| srcp1 += 1; | |
| srcp2 += 1; | |
| res = a0 - b0; | |
| if (res != 0) | |
| return res; | |
| len -= 1; | |
| } | |
| return 0; | |
| } | |
| #ifdef weak_alias | |
| # undef bcmp | |
| weak_alias (memcmp, bcmp) | |
| #endif |